What is the value of [18+{16×(3645÷2425)−(1221×1415÷2445)}+2736]\left[\frac{1}{8} + \left\{ \frac{1}{6} \times \left(\frac{36}{45}\div \frac{24}{25}\right) - \left(\frac{12}{21} \times \frac{14}{15}\div \frac{24}{45}\right)\right\} + \frac{27}{36}\right][81+{61×(4536÷2524)−(2112×1514÷4524)}+3627] ? A136\frac{1}{36}361 B172\frac{1}{72}721 C1108\frac{1}{108}1081 D127\frac{1}{27}271 Show answer & explanationCorrect answer: BExplanationThe correct answer is option 2 i.e. 172\frac{1}{72}721. [18+{16×(3645÷2425)−(1221×1415÷2445)}+2736]\left[\frac{1}{8} + \left\{ \frac{1}{6} \times \left(\frac{36}{45}\div \frac{24}{25}\right) - \left(\frac{12}{21} \times \frac{14}{15}\div \frac{24}{45}\right)\right\} + \frac{27}{36}\right][81+{61×(4536÷2524)−(2112×1514÷4524)}+3627] ⇒ [18+{16×(3645×2524)−(1221×1415×4524)}+2736]\left[\frac{1}{8} + \left\{ \frac{1}{6} \times \left(\frac{36}{45}\times \frac{25}{24}\right) - \left(\frac{12}{21} \times \frac{14}{15}\times \frac{45}{24}\right)\right\} + \frac{27}{36}\right][81+{61×(4536×2425)−(2112×1514×2445)}+3627] ⇒ [18+{16×56−1}+2736]\left[\frac{1}{8} + \left\{ \frac{1}{6} \times\frac{5}{6} - 1\right\} + \frac{27}{36}\right][81+{61×65−1}+3627] ⇒ [18−3136+2736]\left[\frac{1}{8} - \frac{31}{36} + \frac{27}{36}\right][81−3631+3627] ⇒ 36−248+216288\frac{36-248+216}{288}28836−248+216 ⇒ 4288\frac{4}{288}2884 ⇒ 172\frac{1}{72}721