SSC CGL 2023 PYQ — Question 18

SSC CGL Tier II - 26 October 2023 • Quantitative Aptitude • Q18

What is the value of [18+{16×(3645÷2425)−(1221×1415÷2445)}+2736]\left[\frac{1}{8} + \left\{ \frac{1}{6} \times \left(\frac{36}{45}\div \frac{24}{25}\right) - \left(\frac{12}{21} \times \frac{14}{15}\div \frac{24}{45}\right)\right\} + \frac{27}{36}\right] ?

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Correct answer: B

Explanation

The correct answer is option 2 i.e. 172\frac{1}{72}.

[18+{16×(3645÷2425)−(1221×1415÷2445)}+2736]\left[\frac{1}{8} + \left\{ \frac{1}{6} \times \left(\frac{36}{45}\div \frac{24}{25}\right) - \left(\frac{12}{21} \times \frac{14}{15}\div \frac{24}{45}\right)\right\} + \frac{27}{36}\right]

⇒ [18+{16×(3645×2524)−(1221×1415×4524)}+2736]\left[\frac{1}{8} + \left\{ \frac{1}{6} \times \left(\frac{36}{45}\times \frac{25}{24}\right) - \left(\frac{12}{21} \times \frac{14}{15}\times \frac{45}{24}\right)\right\} + \frac{27}{36}\right]

⇒ [18+{16×56−1}+2736]\left[\frac{1}{8} + \left\{ \frac{1}{6} \times\frac{5}{6} - 1\right\} + \frac{27}{36}\right]

⇒ [18−3136+2736]\left[\frac{1}{8} - \frac{31}{36} + \frac{27}{36}\right]

⇒ 36−248+216288\frac{36-248+216}{288}

⇒ 4288\frac{4}{288}

⇒ 172\frac{1}{72}