SSC CHSL 2024 PYQ — Question 66

SSC CHSL - 11 July 2024 - Shift 1 • Quantitative Aptitude • Q66

What is the value of (14÷14×14)×14(18+18×18)+(1−49)\frac{\left( \frac{1}{4} \div \frac{1}{4} \times \frac{1}{4} \right) \times \frac{1}{4}}{\left( \frac{1}{8} + \frac{1}{8} \times \frac{1}{8} \right)} + \left( 1 - \frac{4}{9} \right)?

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Correct answer: D

Explanation

The correct answer is option 4 i.e. 1.

(14÷14×14)×14(18+18×18)+(1−49)\frac{\left( \frac{1}{4} \div \frac{1}{4} \times \frac{1}{4} \right) \times \frac{1}{4}}{\left( \frac{1}{8} + \frac{1}{8} \times \frac{1}{8} \right)} + \left( 1 - \frac{4}{9} \right)

=(14×4×14)×14(18+164)+59=\frac{\left( \frac{1}{4} \times 4 \times \frac{1}{4} \right) \times \frac{1}{4}}{\left( \frac{1}{8} + \frac{1}{64} \right)} + \frac{5}{9}

=14×14964+59=\frac{ \frac{1}{4} \times \frac{1}{4}}{\frac{9}{64} } + \frac{5}{9}

= (1/16)/(9/64) + (5/9)

= (4/9) + (5/9)

= 9/9

= 1

Therefore, the value of the expression is 1.