What is the sum of the digits of the least number, which when divided by 12,16, and 54, leaves the same remainder 7 in each case, and is also completely divided by 13?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 16
LCM of 12, 16, 64 = 432
So,
Required number = 432 + 7 = 439, but it is not divided by 13.
So,
The next number = 432 × 2 + 7 = 871, it is divided by 13
Hence,
Required sum = 8 + 7 + 1 = 16