What is the number of digits required for numbering a book with 428 pages?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 1176.
Given that,
Number of pages = 428
Total numbers from 1 to 9 = 9
Number of digits from 1 to 9 = 9 × 1 = 9
Total numbers from 10 to 99 = 90
Number of digits from 10 to 99 = 90 × 2 = 180
Total numbers from 100 to 428 = 329
Number of digits from 100 to 428 = 329 × 3 = 987
Hence,
The total number of digits = 9 + 180 + 987 = 1176