What is the least number that when divided by 15, 18, and 36 leaves the same remainder of 9 in each case and is divisible by 11?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 1089
LCM of 15, 18 and 36 = 180
The required number which is exactly divisible by 11 = 180x + 9
If x = 6
180 × 6 + 9 = 1089 is divisible by 11.
The required number is 1089.