What is that greatest four-digit number which when divided by 3 and 4 leaves remainder 2 in each case?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 9998.
The general form for a number which when divided by a and b leaves the remainder r in each case is given by = k × LCM(a, b) + r
LCM(3, 4) = 12
Hence, 12k + 2 ≤ 9999
⇒ 12k ≤ 9997
⇒ k ≤ 833.03
Hence k = 833
The number becomes = 833 × 12 + 2 = 9998