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SSC CHSL 2022 PYQ — Question 52

SSC CHSL - 2 June 2022 - Shift 2 • Quantitative Aptitude • Q52

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What distance will be covered by a bus moving at 108 km/h in 40 seconds?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is Option 4 i.e. 1 km 200 m.

Given:

Speed = 108 km/hr

Time = 40 seconds

Formula Used:

Distance = Speed × Time

Speed (in km/hr) = speed × 5185 \over 18 (in m/sec)

Explanation:

The speed in m/sec = 108  × 5185 \over 18 = 30 m/sec

Now, Distance = 30 × 40 = 1200 m = 1 km and 200 m

Hence the required distance is 1 km 200 m.