Two trains start from stations A and B towards each other and meet after 4 hours. Train from A travels 20% faster than train from B. If the distance between A and B is 528 km, find the speed of the slower train.
Show answer & explanation
Correct answer: B
Explanation
Given:
Distance between A and B = 528 km
Meeting time = 4 hours
A's train is 20% faster than B's train
Let the speed of the slower train (B) = x km/h
A's train's speed = 1.2x
Total relative speed = x + 1.2x = 2.2x
Distance = relative speed × time
528 = 2.2x × 4
528 = 8.8x
x = 528 / 8.8
x = 60 km/h