SSC CHSL 2025 PYQ — Question 57

SSC CHSL - 27 Nov 2025 - Shift 1 • Quantitative Aptitude • Q57

A person covers a certain distance in 2 hours. If he had moved 5 km/h faster, he would have taken 30 minutes less. Find the original speed.

Show answer & explanation

Correct answer: C

Explanation

Given:

Distance covered = 2 hours

Increasing speed by 5 km/h = 30 minutes less time = 1.5 hours

Formula:

Distance = Speed ​​× Time

Let initial speed = x km/h

Distance = 2x

New speed = x + 5

New distance = (x + 5) × 1.5

Both distances are equal, so

2x = 1.5(x + 5)

2x = 1.5x + 7.5

2x − 1.5x = 7.5

0.5x = 7.5

x = 15 km/h