Two tangents AP and AQ are drawn to a circle with centre O from an external point A, where P and Q are points on the circle. If the ∠PAQ = 70o, then the ∠AOP is equal to:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e 55o
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Understanding Given ∠PAQ = 70o We have to find ∠AOP |
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Application When we meeting point A to the center O we have two triangle and ∠PAQ has divided into two equal part i.e. ∠PAO and ∠QAO |
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Now In ΔAOP ∠PAO + ∠AOP + ∠OPA = 180 35 + ∠AOP + ∠90 = 180 ∠AOP = 180 - 125 ∠AOP = 55o |