Two parallel chords are drawn in a circle of radius 25 cm. The distance between the two chords is 27 cm. If the length of one chord is 48 cm, then the length of the other chord is equal to:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 30 cm.
BM = 48/2 = 24 cm
OM = √(OB2 - BM2) = √(252 - 242) = √(625 - 576) = √49 = 7 cm
ON = 27 - 7 = 20 cm
DN = √(OD2 - ON2) = √(252 - 202) = √(625 - 400) = √225 = 15 cm
CD = 2DN = 2 × 15 = 30 cm
Hence, the length of another chord is 15 cm.