Two men and 7 women can complete a work in 28 days, whereas 6 men and 16 women can do the same work in 11 days. In how many days will 5 men and 4 women, working together, complete the same work?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 22
Let the efficiency of 1 man and 1 woman be 'm' and 'w'.
According to the question,
(2m + 7w) × 28 = (6m + 16w) × 11
m = 2w....(1)
From eq 1 we can say that if the efficiency of 1 woman is 1 then the efficiency of 1 man is 2.
Total work = (2 × 2 + 7 × 1) × 28 = 11 × 28 = 308 units.
Combined efficiency of 5 men and 4 women = 5 × 2 + 4 × 1 = 14
Time taken = 308/14 = 22 days.