SSC CGL 2020 PYQ — Question 56

SSC CGL Tier II - Quant - 16 Nov 2020 • Quantitative Aptitude • Q56

The denominator of a fraction is 4 more than twice the numerator. When the numerator is increased by 3 and the denominator is decreased by 3, the fraction becomes 23\frac{2}{3}, What is the difference between the denominator and numerator of the original fraction?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 11.

Let the fraction be N/D.

D = 2N + 4.......(1)

When the numerator is increased by 3 and the denominator is decreased by 3, the fraction becomes 23\frac{2}{3},

(N + 3)/(D - 3) = 2/3

3N = 2D - 15..........(2)

On solving equation (1) and (2) we get,

N = 7 and D = 18.

D - N = 18 - 7 = 11.