Two concentric circles are of radii 10 cm and 6 cm. Find the length of the chord of the larger circle which touches the smaller circle.
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Correct answer: B
Explanation
The correct answer is Option 2 i.e 16 cm.

In triangle ABD
⇒ AB2 = AD2 + BD2
⇒ 100 = 36 + BD2
⇒ BD2 = 64
⇒ BD = 8
We know that,
⇒ BC = BD + DC
⇒ BC = 8 + 8 = 16 cm