Two chords AB and CD of a circle intersect each other at P internally. If AP = 3.5 cm, PC = 5 cm, and DP = 7 cm, then what is the measure of PB?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 10 cm
As per the question:
AP = 3.5 cm, DP = 7 cm, PC = 5 cm, PB = ?
As we know that if two chords internally intersecting each other at a point P:
Then, AP × PB = CP × PD
⇒ PB = 5 × 7 ÷ 3.5 = 10