There is a circle with a center T and a radius of 8 cm. Two tangents KE and KI are drawn from point K, which is 17 cm from the center. The area of the quadrilateral TEKI is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 120 sq.cm.
Triangle KET is a right-angle triangle
KT2 = ET2 + KE2
⇒ 172 = 82 + KE2
KE = 15
Area of the right angle triangle KET = Area of the right angle triangle KTI
Area of the right angle triangle KET= 1/2 × base × height = 1/2 × 8 × 15 = 60
So, The area of the quadrilateral TEKI = 2 × 60 = 120