SSC CHSL 2024 PYQ — Question 57

SSC CHSL - 04 July 2024 - Shift 1 • Quantitative Aptitude • Q57

The number nearest to 7658 and exactly divisible by 45 is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 7650.

Given number = 7658

Divisor = 45

Nearest number divisible by divisor is calculated by first dividing the given number by the divisor and then multiplying the integer part of the quotient obtained by the divisor.

According to the given question,

Quotient = 7658/45 = 170.17777

Integer part = 170

Multiplying the integer part by 45,

Nearest number = 170 × 45 = 7650