SSC Selection Post 2020 PYQ — Question 59

SSC Selection Post - Graduation Level 2020 - 10 Nov 2020 - Shift 3 • Quantitative Aptitude • Q59

The volume of a cylinder of height 32 cm and base diameter 36 cm is equal to the volume of a cone of height 24 cm. The curved surface area (in cm2) of the cone is:

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Correct answer: B

Explanation

 The correct answer is Option 2 i.e. 43213π 432\sqrt13 \pi.

Radius (r) = 18 cm

Volume of cylinder = πr2h = π × 182 × 32 = 10368π cm3

Let the radius of the cone = R cm

(1/3)π × R2 × 24 = 10368π

⇒ R2 = (10368 × 3)/24 = 1296

⇒ R = 36cm

Slant height (L) = √(362 + 242) = √1872 = 12√13 cm

Curved surface area = πRL = π × 36 × 12√13 = 432√13π cm3