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SSC Selection Post 2020 PYQ — Question 58

SSC Selection Post - Graduation Level 2020 - 10 Nov 2020 - Shift 3 • Quantitative Aptitude • Q58

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In ΔABC, ∠B = 90°, AC = 29 cm, and BC = 20 cm. Then (1−sinA+cosA)(1+sinA+cosA)(1 - sin A + cos A)\over(1 + sin A + cos A) is equal to:

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Correct answer: B

Explanation

 The correct answer is Option 2 i.e. 37\frac{3}{7}.

AB = √(AC2 - BC2) = √(292 - 202) = √(841 - 400) = √441 = 21 cm

sin A = BC/AC = 20/29

cos A = AB/AC = 21/29

(1 - sin A + cos A)/(1 + sin A + cos A)

= (1 - 20/29 + 21/29)/(1 + 20/29 + 21/29)

= (30/29)/(70/29)

= 3/7