The value of the expression 4sin230∘+cos260∘−tan245∘2sin60∘cos30∘−tan45∘ \frac{4sin^230^\circ+cos^260^\circ- tan^245^\circ}{2sin60^\circ cos30^\circ-tan45^\circ}2sin60∘cos30∘−tan45∘4sin230∘+cos260∘−tan245∘is : A12\frac{1}{\sqrt2}21 B12\frac{1}{2}21 C14\frac{1}{4}41 D1 Show answer & explanationCorrect answer: BExplanationThe correct answer is Option 2 i.e. 12\frac{1}{2}21. 4sin230∘+cos260∘−tan245∘2sin60∘cos30∘−tan45∘ \frac{4sin^230^\circ+cos^260^\circ- tan^245^\circ}{2sin60^\circ cos30^\circ-tan45^\circ}2sin60∘cos30∘−tan45∘4sin230∘+cos260∘−tan245∘ =4(12)2+(12)2−(1)22(32)(32)−1=\frac{ 4\left(\frac{1}{2}\right)^2 + \left(\frac{1}{2}\right)^2 - (1)^2}{ 2\left(\frac{\sqrt{3}}{2}\right)\left(\frac{\sqrt{3}}{2}\right) - 1}=2(23)(23)−14(21)2+(21)2−(1)2 =4(14)+14−12(34)−1=\frac{4\left(\frac{1}{4}\right) + \frac{1}{4} - 1}{2\left(\frac{3}{4}\right) - 1}=2(43)−14(41)+41−1 =1+14−132−1=\frac{1 + \frac{1}{4} - 1}{\frac{3}{2} - 1}=23−11+41−1 = (1/4)/(1/2) = 1/2