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SSC CGL 2019 PYQ — Question 51

SSC CGL - 11th June 2019 - Shift 2 • Quantitative Aptitude • Q51

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The value of cot262° - sec228° + cosec230° + tan260° is equal to:

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Correct answer: D

Explanation

Correct Answer is option 4 i.e. 6

Concept

Application

Cot(90 - θ) = tan θ

and 

Sec2θ – tan2θ = 1

Cot262° - sec228° + cosec230° + tan260° 

⇒ cot2(90° - 28°) – sec228° + 22 + (√3)2 

⇒ tan228 – sec228 + 4 + 3 

⇒ 7 - 1 

⇒ 6