The value of ((Cos9o + Sin81o)(Sec9o + Cosec81o))/(2Sin263o + 1 + 2Sin227o) is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e 4/3.
| Understanding/Application |
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((Cos90 + Sin810)(Sec90 + Cosec810))/(2Sin2630 + 1 + 2Sin2270) = {(cos(90 - 81) + sin810)(sec(90 - 81) + cosec810)}/{(2sin2630 + 1 + 2sin2(90 - 63)} |
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= {(sin810 + sin810)(cosec810 + cosec810)}/(2sin2630 + 1 + 2cos2630) = {(2sin810) (2cosec810)}/(3) = 4/3 |