Four men and 6 women can complete a certain piece of work in 5 days whereas three men and 4 women can complete it in 7 days. How many men should assist 25 women to complete 
times the same work in 5 days?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e 5.
| Understanding/Application |
|
According to the question - (4m + 6w)5 = (3m + 4w)7 20m + 30w = 21m + 28w 1m = 2w (Here, m = men and w = women) Total work done to be done = (8w + 6w)5 = 70 units Work to be done = 70(5)/2 = 175 units |
|
Work done by 25 women in 5 days = 25(5) = 125 units Work left to be done in 5 days by men = 175 - 125 = 50 units Work done by 1 women = 1 unit Work done by 1 man in 1 day = Double of that by 1 woman = 2 units Work done by 1 man in 5 days = 2(5) = 10 units Total number of men who assist work = Remaining work/Work done by 1 man in 5 days = 50/10 = 5 men |