SSC CPO 2024 PYQ — Question 101

SSC CPO - 29 June 2024 - Shift 3 • Quantitative Aptitude • Q101

The value of 61+25×75÷6−(3×6÷12)166+23×(58−37) { {61 + \frac{2}{5} × 75 ÷ 6 - (3 × 6 ÷ \frac{1}{2}) \frac{1}{6}} \over 6 + \frac{2}{3} × (58 - 37)}  .

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 3.

61+25×75÷6−(3×6÷12)166+23×(58−37) { {61 + \frac{2}{5} × 75 ÷ 6 - (3 × 6 ÷ \frac{1}{2}) \frac{1}{6}} \over 6 + \frac{2}{3} × (58 - 37)}

⇒ 61+25×675−(3×6×2)166+23×21 { {61 + \frac{2}{5} × \frac{6}{75} - (3 × 6 × 2) \frac{1}{6}} \over 6 + \frac{2}{3} × 21}

 ⇒ 61+25×756−66+14 { {61 + \frac{2}{5} × \frac{75}{6} -6} \over 6 + 14}

 ⇒ 61+5−65+14 { {61 + 5 -6} \over 5 + 14}

 ⇒ 3