An alloy contains the metals A, B and C in the ratio 2 : 3 : 1 and another contains the metals B, C and D in the ratio 5 : 4 : 3. If equal weights of both alloys are mixed together to form a third alloy, then how much part of the metal B is in new alloy?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. .
Consider equal weights of both alloys are 1 unit each.
Alloy 1: A, B, C in the ratio 2:3:1
Total parts of alloy 1 = 2 + 3 + 1 = 6
Weight of B in alloy 1 = 3 / 6 = 1/2
Alloy 2: B, C, D in the ratio 5 : 4: 3
Total parts of alloy 2 = 5 + 4 + 3 = 12
Weight of B in alloy 2 = 5 / 12
Total weight of B in the new alloy = 1/2 + 5/12 = 11/12
Total weight of the new alloy (since equal weights are mixed) = 1 + 1 = 2
Part of metal B in the new alloy = (11/12) / 2 = 11/24