SSC CHSL 2021 PYQ — Question 53

SSC CHSL - 19 April 2021 - Shift 2 • Quantitative Aptitude • Q53

The value of 3cos227°−5+3cos263°tan232°+4−cosec258°\frac{3 cos^2 27° - 5 + 3 cos^263°}{ tan^232° + 4 - cosec^258°} + sin35°cos55°+ cos35°sin55° is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 13\frac{1}{3}

Concept USed:

cos(90 - A) = sinA

tan(90 - A) = cotA

sin2A + cos2A = 1

cosec2A - cot2A = 1

Explanation:

According to the given question,

  3cos227°−5+3cos263°tan232°+4−cosec258°\frac{3 cos^2 27° - 5 + 3 cos^263°}{ tan^232° + 4 - cosec^258°} + sin35°cos55°+ cos35°sin55°

⇒  3cos2(90−63°)−5+3cos263°tan2(90−58°)+4−cosec258°\frac{3 cos^2 (90 - 63°) - 5 + 3 cos^263°}{ tan^2(90 - 58°) + 4 - cosec^258°} +sin(90 - 55°)cos55°+ cos(90 - 55°)sin55°

⇒ 3sin263°−5+3cos263°cot258°+4−cosec258°\frac{3 sin^2 63° - 5 + 3 cos^263°}{ cot^258°+ 4 - cosec^258°}+ cos55°cos55°+ sin55°sin55°

⇒ 3(sin263°+cos263°)−5(cot258°−cosec258°)+4\frac{3 (sin^2 63° + cos^263°) - 5}{ (cot^258° - cosec^258°) + 4}+ cos255°+ sin255°

⇒ 3−5−1+4\frac{3 - 5}{ -1 + 4}+ 1

⇒ −23\frac{-2}{3}+ 1

 ⇒ 13\frac{1}{3} 

Hence the required answer is 13\frac{1}{3}.