The value of 323÷215×14×(1+31−25)3 \frac{2}{3} \div 2\frac{1}{5} \times {1 \over 4} \times {(1 + {3\over{1 - {2\over 5}}}})332÷251×41×(1+1−523) is:A2142 \frac{1}{4}241B1321 \frac{3}{2}123C3123 \frac{1}{2}321D2122 \frac{1}{2}221Show answer & explanationCorrect answer: DExplanationThe correct answer is Option 4 i.e. 2122 \frac{1}{2}221. 323÷215×14×(1+31−25)3 \frac{2}{3} \div 2\frac{1}{5} \times {1 \over 4} \times {(1 + {3\over{1 - {2\over 5}}}})332÷251×41×(1+1−523) ⇒ 113÷115×14×(1+35−25)\frac{11}{3} \div \frac{11}{5} \times {1 \over 4} \times {(1 + {3\over{5 - 2\over 5}}})311÷511×41×(1+55−23) ⇒ 113×511×14×(1+335)\frac{11}{3} \times \frac{5}{11} \times {1 \over 4} \times {(1 + {3\over{3\over 5}}})311×115×41×(1+533) ⇒ 113×511×14×(1+153)\frac{11}{3} \times \frac{5}{11} \times {1 \over 4} \times {(1 + {15\over{3}}})311×115×41×(1+315) ⇒ 53×14×(1+5)\frac{5}{3} \times {1 \over 4} \times {(1 + 5})35×41×(1+5) ⇒ 53×14×6\frac{5}{3} \times {1 \over 4} \times635×41×6 ⇒ 5×14×25\times {1 \over 4} \times25×41×2 ⇒ 52{5 \over 2} 25 = 2122 \frac{1}{2}221