A hemispherical bowl is 88 cm around the brim. Assuming it to be full, how many
persons may be served from it in hemispherical glasses, 7 cm in diameter at the
top? (Where π = 22/7)
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 64.
Let the number of glasses be n
We will first find out the radius,
Circumference = 88
Now,
Circumference of the circle = 2πr
⇒ 88 = 2 × 22/7 × r
⇒ r = (88 × 7)/44
⇒ r = 14 cm
Now, the volume of the hemispherical ball
Volume = 2/3 × π × r3
⇒ 2/3 × 22/7 × 14 × 14 × 14
⇒ (2 × 22 × 2744)/(3 × 7)
⇒ 120736/21 ≈ 5749.33 cm3
Now,
Given the diameter of each glass is 7 cm, the radius r of each glass is:
⇒ r = 7/2 = 3.5
Now, the volume of each hemispherical glass
Volume = 2/3πr3
⇒ 2/3 × 22/7 × 3.5 × 3.5 × 3.5
⇒ 1886.5/21 ≈ 89.33 cm3
Now, the number of glasses = volume of the hemispherical ball/volume of each hemispherical glass
⇒ n = 5749.33/89.33
⇒ n = 64.30 ≈ 64
Thus, approximately 64 people may be served from the bowl.