SSC CPO 2019 PYQ — Question 116

The correct answer is Option 1 i.e. 0.15 and 0.2.

$({1\frac{1}{9}} \times {1\frac{1}{20}} \div {21\over38} - {1\over 3}) \div ({2\frac{4}{9}}\div {1\frac{7}{15}} of {3\over5}) \over{1\over5} of {1\over5} \div {1\over125} - {1\over25}\div {1\over5} of {1\over5}$

⇒ {(10/9 × 21/20 ÷ 21/38 - 1/3) ÷ (22/9 ÷ 22/15 of 3/5)}/{(1/5 of 1/5 ÷ 1/125 - 1/25 ÷ 1/5 of 1/5)}

⇒ {(10/9 × 19/10 - 1/3) ÷ (25/9)}/{(5 - 1)}

⇒ {(19/9 - 1/3) ÷ (25/9)}/4

⇒ {16/9 ÷ 25/9}/4

⇒ (16/25)/4

⇒ 16/100

⇒ 0.16

Hence, It is lies between 0.15 and 0.2