SSC CGL 2020 PYQ — Question 64

SSC CGL - 7 March 2020 Shift 2 • Quantitative Aptitude • Q64

The value of 1(1/8) ÷ (4(1/4) ÷ 3/5 of 8(1/2) - 2/5 × 1(1/3) ÷ 4/5 of 1(2/3) + 11/20) is:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e.

By solving using BODMAS,

⇒ 1(1/8) ÷ (4(1/4) ÷ 3/5 of 8(1/2) - 2/5 × 1(1/3) ÷ 4/5 of 1(2/3) + 11/20)

⇒ (9/8) ÷ (17/4) ÷ 3/5 of 17/2 - 2/5 × 4/3 ÷ 4/5 of 5/3 + 11/20)

⇒  (9/8) ÷ (17/4) ÷ 51/10 - 2/5 × 4/3 ÷ 4/3 + 11/20)

⇒  (27/20 - 2/5 × 1 + 11/20)

⇒  (27/20 - 2/5 + 11/20)

⇒ (38/30 - 2/5)

⇒ 30/20 = 3/2

⇒