In quadrilateral PQRS, RM ⊥ QS, PN ⊥ QS and QS = 6 cm. If RM = 3 cm and PN = 2 cm, then the sum of the area of quad PQRS and △SQR is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 23 cm2.
It is given that,
QS = 6 cm, RM = 3 cm, PN = 2 cm
Area of PQRS = Area of triangle PQS + Area of triangle SQR
⇒ ((1/2) × 2 × 6) + ((1/2) × 3 × 6)
⇒ 6 + 9
⇒ 15 cm2
Thus, the sum of quad PQRS and △SQR = 15 + 9 = 24 cm2