The total numbers of males and females in a town is 70,000. If the number of males is increased by 6% and that of the females is increased by 4%, then the total numbers of males and females in the town would become 73520. What is the difference between the number of males and females in the town, in the beginning?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 2000
| Understanding | Application |
| Tricks |
let number of male = x number of female = y |
| According to question |
x + y = 70,000 ........i) & 6x/100 + 4y/100 = 3520 ⇒ 6x + 4y = 352,000 .....ii) |
| Now |
After solving both eauation x = 36000 y = 34000 |
| Hence |
Difference = 36000 - 34000 2000 |