Pipes A and B can fill a tank in 36 hours and 48 hours, respectively. Both pipes are opened together for 9 hours and then A is closed. Pipe B alone will fill the remaining part of the tank now in:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e.27 hours
| Understanding/Application |
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Given, A = 36 hr B = 48 hr Total strength of the tank = LCM of 36 and 48 = 144 liters Efficiency of A = 144/36 = 4 Efficiency of B = 144/48 = 3 Here, Working 12 hours together. Now, remaining work = 144 - (4 + 3)9 = 144 - 63 = 81 liters Remaining work done by B. Hence, Required time = (remaining work/Efficiency of B) = 81/3 = 27 hours
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