The sum of three numbers is 98. The second number is twice the first, and the third number is 2 less than the second. Find the numbers.
Show answer & explanation
Correct answer: D
Explanation
Sum of three numbers = 98
The second number = twice the first
The third number = 2 less than the second
Let the first number = x
The second number = 2x
The third number = 2x − 2
x + 2x + (2x − 2) = 98
5x − 2 = 98
5x = 100
x = 20
The second number = 40
The third number = 38
20, 40, 38