The sum of squares of three positive integers is 323. If the sum of squares of two numbers is twice the third, their product is ?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option1
Now, a2 + b2 + c2 = 323 .....(1)
And, a2 + b2 = 2c .....(2)
using (1) and (2)
2c + c2 = 323
c2+2c - 323 = 0
(c + 19)(c - 17) = 0
c = 17, c = -19
But c is not equal to -19
Now, a2 + b2 = 34
a = 2 and b = 5 satisfy the equation
abc = 3 × 5 × 17 = 255