The sum of 17 consecutive numbers is 289. The sum of another 10 consecutive numbers, whose first term is 5 more than the average of the first set of consecutive numbers, is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 265.
| Understanding/Application |
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Sum of 17 consecutive numbers = 289 Sum of consecutive numbers = [n/2 × (1st term + last term)] Average of 17 consecutive numbers = (289/17) = 17 |
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Acc. to the question - The first term of other 10 consecutive numbers = 17 + 5 = 22 Ten numbers will be 22, 23, 24, 25, 26, 27, 28, 29, 30, 31. Sum of the another consecutive numbers = [{10/2 × (22 + 31)}] = 5(53) = 265 |