If A and B are acute angles and SecA = 3; CotB = 4, then the value of
is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e 322/323.
| Understanding/Application |
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secA = 3 cosA = 1/3 sinA = √(1 - cos2A) = √{1 - (1/9)} = √(8/9) = 2√2/3 cosecA = 3/2√2 cotA = cosA/sinA = (1/3)/(2√2/3) = 1/2V2 cotB = 4 tanB = 1/4 secB = √(1 + tan2B) = √(1 + 1/16) = √(17/16) = √17/4 cosB = 4/√17 sinB = √(1 - cos2B) = √(1 - 16/17) = 1/√17 |
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(cosec2A + sin2B)/(cot2A + sec2B) = {(3/2√2)2 + (1/√17)2}/{(1/2√2)2 + (√17/4)2} = (9/8 + 1/17)/(1/8 + 17/16) = (161/136)/(152/128) = 322/323 |