SSC Selection Post 2023 PYQ — Question 57

SSC Selection Post - Graduation Level - 30 June 2023 - Shift 1 • Quantitative Aptitude • Q57

The solution of the equation cos2θ{{\theta}} + sin θ{{\theta}} + 1 = 0 lies between:

Show answer & explanation

Correct answer: B

Explanation

 The correct answer is Option 2 i.e. (5π4,7π4)({{5π} \over 4},{{7π} \over 4}).

cos2θ + sinθ + 1 = 0

⇒ 1 - sin2θ + sinθ + 1 = 0

⇒ sin2θ - sinθ - 2 = 0

⇒ (sinθ + 1)(sinθ - 2) = 0

⇒ sinθ = -1 = sin(3π/2)

⇒ θ = (3π/2) = (6π/4) ∈ (5π4,7π4)({{5π} \over 4},{{7π} \over 4})