SSC MTS 2022 PYQ — Question 56

SSC MTS - 21 July 2022 - Shift 3 • Quantitative Aptitude • Q56

The radius of the base and the height of a closed cylinder are 14 cm and 14 cm, respectively. The total surface area of the cylinder is equal to the area of a circle. What will be the diameter of the circle? [Use pi = 22/7 ]

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 56 cm

The total surface area of a cylinder is given by:

2πr(r + h)

where r is the radius of the base, h is the height of the cylinder, and π is the constant pi.

In this problem, we have r = 14 cm and h = 14 cm. Therefore, the total surface area of the cylinder is:

2π(14) (14 + 14) = 2π(14) (28) = 784π sq.cm

The area of a circle is given by:

πr2

where r is the radius of the circle.

πr2 = 784π

r2= 784

r = √784 = 28

The diameter of the circle is twice the radius, so:

d = 2r = 2(28) = 56 cm

Therefore, the diameter of the circle is 56 cm.