SSC GD 2024 PYQ — Question 56

The correct answer is option 3 i.e. 237.5 percent.

the volume of a sphere (v) = 4/3 ​πr³

Let the initial radius = r

If the radius is increased by 50%

the new radius = r + 0.50r = 1.50r

The new volume of the sphere (v₂) = 4/3π(1.50r)³ = 4/3π × 1.50³ × r³

⇒ 4/3π × 3.375 × r³ = 3.375 × V_1​

Percentage increase = (v₂ - v₁)/v₁ × 100 = (​3.375V₁​ − V₁)​​/v₁ × 100

⇒ 2.375V₁/V₁ × 100 = 237.5%