The radius of a circle is 5 cm, and the length of one of its chords is 8 cm. Find the distance of the chord from the center.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 3 cm.
OC is perpendicular to AB and bisects AB in two equal parts
AC = 8/2 = 4 cm
OC2 = AO2 - AC2 = 52 - 42 = 25 - 16 = 9
⇒ OC = √9 = 3
Hence, the distance between the centre and the chord is 3 cm.