The length of the chord of a circle is 8 cm and the perpendicular distance between the centre and the chord is 3 cm then the diameter of the circle is equal to:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 10 cm.
OC is perpendicular to AB and bisects AB in two equal parts
AC = 8/2 = 4 cm
AO2 = OC2 + AC2 = 32 + 42 = 9 + 16 = 25
⇒ AO = √25 = 5
Diameter = 2AO = 2(5) = 10 cm
Hence, the diameter is 10 cm.