The radius of a circle is 10 cm. The angle made by chord AB at the center of this circle is 60 degrees. What is the length of this chord?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 10 cm.

OA = OB = 10 cm
ΔOAB is an isosceles triangle.
So, ∠OAB = ∠OBA = = 60°
Since ∠OAB = ∠OBA = ∠OAB = 60°, ΔOAB is an equilateral triangle.
So, OA = OB = AB = 10 cm
The length of the chord is 10 cm.