The price of an item is increased twice successively. The final price is ₹2,295 and initial price was ₹1,000. The percentage increment the second time was twice the percentage increment the first time. By what percentage was the price increased the second time?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 70%.
Let the percentage increase the first time be x% and the second time be 2x%.
Initial price of the item = ₹1,000
Final price of the item = ₹2,295
So,
⇒
⇒ 1 + (3x/100) + (2x2/10000) = 2.295
⇒ (3x/100) + (2x2/10000) = 2.295 - 1 = 1.295
⇒ 300x + 2x2 = 12950
⇒ 2x2 + 300x - 12950 = 0
⇒ x2 + 150x - 6475 = 0
⇒ x2 + 185x - 35x - 6475 = 0
⇒ x(x + 185) - 35(x + 185) = 0
⇒ (x + 185)(x - 35) = 0
⇒ x = - 185 (Negative value not possible)
⇒ x = 35
⇒ 2x = 2 × 35 = 70
Therefore, the price increased the second time by 70%.