The possible value of x satisfying (143 ÷ 13 × x - 3 times3)over (6² -7times5+x²) = 1 is:

The possible value of x satisfying (143 ÷ 13 × x - 3…

The possible value of x satisfying $(143 \div 13 \times x - 3 \times3)\over (6^2 -7\times5+x^2)$ = 1 is:

Show answer & explanation

Correct answer: B

Explanation

The correct answer is Option 2 i.e 1.

$(143 \div 13 \times x - 3 \times3)\over (6^2 -7\times5+x^2)$ = 1

⇒ 143 ÷ 13 × x - 3 × 3 = 6² - 7 × 5 + x²

⇒ 11 × x - 9 = 36 - 35 + x²

⇒ 11x - 9 = 1 + x²

⇒ x² - 11x + 10 = 0

⇒ x² - 10x - x + 10 = 0

⇒ x(x - 10) - 1(x - 10)

⇒ (x - 1)(x - 10)

⇒ x = 1, 10

(x = 10 is not in options)