The income of X is 42% more than that of Y, and the income of Z is 45% less than the sum of the incomes of X and Y. By what per cent is the income of Z less than the income of X (correct to one decimal place)?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 6.3%.
Let Y's income = 100
X's income = 142
Combined income of X and Y = 142 + 100 = 242
Z's income = (55/100) × 242 = 133.10
X - Z = 142 - 133.10 = 8.90
Percentage = (8.90/142) × 100 ≈ 6.3%