The distance between two stations, A and B, is 428 km. A train starts from station ‘A’ at 6:00 a.m. and moves towards station ‘B’ at an average speed of 48 km/h. Another train starts from station ‘B’ at 6:20 a.m. and moves towards station ‘A’ at an average speed of 55 km/h. at what time will the trains meet?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e 10:20 a.m.
| Understanding/Application |
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Distance from A to B = 428 km Speed of train A = 48 km/hr Speed of train B = 55 km/hr Train A starts at 6:00 a.m. and Train B starts at 6:20 a.m. Distance covered by train A in 20 min = (48 × 20)/60 = 16 km Remaining distance = 428 - 16 = 412 km |
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Train run in opposite direction so relative speed = 48 + 55 = 103 km/hr Time taken to meet = 412/103 = 4hr Time when trains meet = 6:20 + 4 = 10:20 a.m. |