In the figure, Two circles with centres P and Q touch externally at R. Tangents AT and BT meet the common tangent TR at T. if AP = 6 cm and PT = 10 cm, then BT =?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e 8 cm.
| Understanding/Application |
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In right-angled ΔPAT [90 at A], PT2 = AP2 + AT2 ⇒ 102 = 62 + AT2 ⇒ AT2 = 100 - 36 = 64 ⇒ AT = √64 = 8 cm |
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As we know, AT = TR = 8 cm [common tangent] TR = TB = 8 cm [common tangent] |