SSC CHSL 2024 PYQ — Question 54

The correct answer is Option 4 i.e. 16 π cm³.

The curved surface area (CSA) of a cone = πrl

here, r = radius, and l = slant height

Now,

⇒ 20π = π × 4 × l

⇒ l = 5 cm

Now,

In a right circular cone,

⇒ l² = r² + h²

⇒ 5² = 4² + h²

⇒ h² = 25 - 16

⇒ h² = 9

⇒ h = 3

Now,

The volume of a cone(V) = 1/3πr²h

here, h = height of the cone

⇒ V = 1/3 × π × 4² × 3

⇒ V = 16π cm³