The area of a circular path enclosed by two concentric circulars is 3080m2. If the difference between the radius of the outer edge and of the inner edge of the circular path is 10 m, what is the sum (in m) of the two radii? ( Taken π=)
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Correct answer: D
Explanation
The correct answer is option 4 i.e. 98
Area of circular path = π(R2 - r2) = 3080
22/7 × (R + r)(R - r) = 3080
22/7 × (R + r) × 10 = 3080
(R + r) = 98.